Question

If 4^( x + 1 ) + 4^( x - 1 ) + 4^( x + 2 ) = 2592 then find value of x

Answer 1

4^(x+1)+4^(x-1)+4^(x+2)=2592

4^x•4 +4^x/4+4^x•4²=2592

4^x{4+1/4+16}=2592

4^x{81/4}=2592

4^x=128

2^2x=2^7

2x=7

x=7/2

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