Math, asked by Tanvi8299, 8 months ago

If 4^x+1-4x=24,then what is the value of (2x)^x?

Answers

Answered by RvChaudharY50
0

Answer:

4x²-4x +1 = 24

(2x-1)² = 24

(2x-1) = √24

2x = (√24)+1

(2x)^x = [(√24)+1]^{(√24)+1/2}

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