Question

If 4 x 1019 electrons passes through a conducting wire in 2 minutes, then the current in the wire is
OPTIONS
MARK FOR REVIEW
O A) 53.33 mA
B) 6.67 mA
O C) 56.65 A
D) 0.77 mA​

Answer 1

Step-by-step explanation:

charge=q=ne=4×10^19×(1.6×10^-19) as e =charge on electron

So, q=4×1.6=6.4 C

and current =charge / time =6.4/2min

=6.4/2×60 =0.05333A =53.33 mA as 1mA=10^-3A