If 4 x² +9 y²=18 and xy=1, find the value of(2x-3y)
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(2x-3y)²= (2x)²+(9y)²-2xy
=4x²+9y²-2
=18-2
=16
so, 2x-3y=√16
= 4
=4x²+9y²-2
=18-2
=16
so, 2x-3y=√16
= 4
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Answer:
4 by 3 minus 3 by 4 and whole square + 2 equal 16 by 9 m square + 9 by 16 n square
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