IF 40 GM OF METHANE IS BURNT THEN HOW MUCH AMOUNT OF CO2 IS RELEASED?
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Your reaction will produce 100 g of carbon dioxide.
Start by writing the balanced chemical equation for the combusiont of methane
CH4(g)+2O2(g)→CO2(g)+2H2O(l)
Notice that you have a 1:1 mole ratio between methane and carbon dioxide. This means that the number of moles of carbon dioxide produced will be equal to the number of moles of methane that reacted.
To determine how many moles of methane react, use the compound's molar mass
40g⋅1 mole CH416.04g=2.49 moles CH4
The reaction will thus produce
2.49molesCH4⋅1 mole CO21moleCH4=2.49 moles CO2
To get the mass of carbon dioxide that would contain this many moles, use the compound's molar mass
2.49moles⋅44.01 g1mole=109.6 g CO2
Rounded to one sig fig, the number of sig figs you gave for the mass of methane, the naswer will be
mCO2=100 g CO2
Start by writing the balanced chemical equation for the combusiont of methane
CH4(g)+2O2(g)→CO2(g)+2H2O(l)
Notice that you have a 1:1 mole ratio between methane and carbon dioxide. This means that the number of moles of carbon dioxide produced will be equal to the number of moles of methane that reacted.
To determine how many moles of methane react, use the compound's molar mass
40g⋅1 mole CH416.04g=2.49 moles CH4
The reaction will thus produce
2.49molesCH4⋅1 mole CO21moleCH4=2.49 moles CO2
To get the mass of carbon dioxide that would contain this many moles, use the compound's molar mass
2.49moles⋅44.01 g1mole=109.6 g CO2
Rounded to one sig fig, the number of sig figs you gave for the mass of methane, the naswer will be
mCO2=100 g CO2
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100 g
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