If 40 grams of saturated solution of common salt at 40oC is cooled to 15oC. How many grams of salt will be precipitated if the solubility of salt at 40oC is 29 and at 15o C is 23?
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weight of salt = 90 gram,
solubility = 50
sing formula
solubility of solute =
weightofsolventinsaturatedsolution
weightofsoluteinsaturatedsolution
×100
or 50=
weightofsolventinsaturatedsolutio
90gm
×100
so weight of solvent in saturated solution =
50
90gm
×100=180gm
Hence 180 gm of water is required to prepare a saturated solution.
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