Question

If 400 g boiling water at 1000C is poured on a large slab of ice at 0 0C, how much ice will melt?(Specific heat capacity of water is 1 cal/g 0Cand Latent heat of fusion of ice is 80 cal/g).

Answer 1

Answer:

500 gms of ice melts

Explanation:

Heat lost by water to go from 100°C ⇒ 0°C

$Q=m(S_w_a_t_e_r)(\triangle T)\\\\Q=(400)(1)(100)\\\\\boxed{Q=4X10^{4}cal}----(1)$

Now since this heat lost by water is gained by ice, the amount that has melted is given by :-

$Q=m(L_f_u_s_i_o_n)\\\\\boxed{Q=(m)(80)}----(2)$

Since Heat gained = Heat lost ⇒ (1) = (2) :-

$=> 40000=80(m)\\\\=> \boxed{m=500gms}$

Hope this answer helped you :)

Answer 2

Given,

If 400g boiling water at 100°C is poured on a large slab of ice at 0°C. specific heat capacity of water, S = 1 cal/g/°C and latent heat of fusion of ice, Lf = 80 cal/g

To find,

The amount of ice will melt.

amount of water, m₁ = 400g

change in temperature, ∆T = 100° C

from calorimetry,

heat lost by water = heat gained by ice

⇒m₁S∆T = mLf

⇒400g × 1cal/g/°C × 100°C = mLf

⇒40000 = m × 80 cal/g

⇒m = 500 g

Therefore 500g of ice will melt.

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