Math, asked by lrkulhari7326, 5 days ago

If 40kg of fish is required in a marriage reception having 250guests then what will be the additional quantity of fish required for 300guests

Answers

Answered by 2008vivekjadhav
0

if 250guests have 40kg fish 300guests have 300*40/250=48kg 48kg-40kg=8kg. :- 8kg

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Answered by chandan454380
1

Answer

Additional quantity of fish required for 300 guests is 8 kg

Step-by-step explanation:

Here the given problem,40 kg of fish is required in a marriage reception having 250 guests

So for 1 guest required fish is 40÷250 =0.16 kg

And for 300 guests required fish is 0.16×300=48kg

So the additional quantity of fish required for 300 guests is (48-40)=8 kg.

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