Question

If 43 times of two digit numbers is 34 times reverse of two digit no .And sum of ( number and reverse of the number) is 14 then what is the number?

Answer 1

Answer:

The number is 68.

Step-by-step explanation:

43 ( 10 x + y ) = 34 ( 10 y + x )

430 x + 43 y = 340 y + 34 x

430 x - 34 x = 340 y - 43 y

396 x = 297 y

We also know that : x + y = 14

y = 14 - x

396 x = 297 ( 14 - x )

396 x = 4158 - 297 x

693 x = 4158

x = 4158 : 693,   x = 6

y = 14 - 6 = 8

Prove: 43 * 68 = 34 * 86

2924 = 2924

Therefore this number is 68 (the reverse is 86).

Answer 2

Step-by-step explanation:

The number is 68

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