Question

If x be the mid-point and 1 be the upper-class limit of a class in a continuous frequency distribution. What is the lower limit of the class?

Answer 1

Hey dude, your answer is here,

Let x and y be the lower and upper class limit of a continuous frequency distribution

Now, mid-point of a class = (x+y) /2=m (given)

X+y=2m=x+l=2m

[ therefore y=l=upper class limit (given)]

X=2m-l

Hence, the lower class limit of the class is 2m-l

Thank you friend

Answer 2

The lower limit of the class = 2x - 1

Given :

x be the mid-point and 1 be the upper-class limit of a class in a continuous frequency distribution

To find :

The lower limit of the class

Solution :

Step 1 of 2 :

Write down mid - point and upper-class limit

Here it is given that x be the mid-point and 1 be the upper-class limit of a class in a continuous frequency distribution

Mid - point = x

Upper-class limit = 1

Step 2 of 2 :

Find lower limit of the class

Let lower limit of the class = y

So by the given condition

$\displaystyle \sf{ \frac{1 + y }{2} = x}$

$\displaystyle \sf{ \implies 1 + y = 2x}$

$\displaystyle \sf{ \implies y = 2x - 1}$

Lower limit of the class = 2x - 1

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