Question

if 43x1 is a multiple of 3 where x is a single digit what are the possible values of x

Answer 1

if 43x1 is a multiple of 3

then the sum of its digits i.e.4+3+x+1=8+x must be a multiple of 3

the multiple of 3 are 3,6,9,12,15,18,21,etc.

8+x=9 or 8+x=12 or 8+x=15

therefore the possible values of x are 1,4,7

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Answer 2

Given:

4 digit number 43$x$1 which is a multiple of 3

To Find:

Possible values of $x$

Solution:

Divisibility Rule of 3:

''A whole number is said to be divisible by 3 if the sum of all digits of that whole number is a multiple of 3 or exactly divisible by 3.''
The given number is 43$x$1  so we will add all the digits first.

4+3+$x$+1= 8+$x$

The multiples of 3 are 9,12,15,18,.....

when, $x$ = 1

⇒8+1 = 9

when, $x$ = 4

⇒8+4 = 12

when, $x$ = 7

⇒8+7 = 15

Hence,  the possible values of $x$ are 1, 4 and 7.