Question

If 49g of h2so4 is present in 500g of water then the molality

Answer 1

Hi there,

■ Key :

☆ Molality is number of solute moles present in mass in kg of solvent

■ Given :

☆ Sample mass of H2SO4 = 49g

☆ Molar mass of H2SO4 = 98

☆ Mass of water in Kg = 0.5 kg

So,

♤ Number of moles of H2SO4

☆ 49 g × 1mol / 98 gm = 0.5 mol

☆ m = 0.5 mol / 0.5 Kg = 1 m

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