Question

If 4cosA =3sinA then the value of 2sinA + 3cosA = ?

Answer 1

Answer:

$\frac{17}{5}$

Step-by-step explanation:

$\tan( \alpha ) = \frac{4}{3} \\ \\ \ \sin( \alpha ) = \frac{4}{5} \\ \\ \cos( \alpha ) = \frac{3}{5} \\ \\ 2 \sin( \alpha ) + 3 \cos( \alpha ) = 2 \times \frac{4}{5} + 3 \times \frac{3}{5} \\ \\ \frac{8}{5} + \frac{9}{5} \\ \\ = \frac{17}{5}$