if 4cotA=3 find (i)sinA (ii)secA (iii)cosec^2A
-cot^2A
Answers
Answered by
1
Answer:
cotA = 3/4
cosecA= √1+cot² = √1+9/16 = √25/16 = 5/4
sinA= 1/cosecA = 4/5
cotA =cosA/sinA =
3/4 = cosA / 4/5
cosA = 3/4 ×4/5 = 3/5
sec= 1/cosA = 5/3
cosec²A -cot²A = 1
Similar questions