Math, asked by Raajeswari2942, 1 year ago

If 4i + (2p/3) j + pk is parallel to the vector i + 2j + 3k, find p.

Answers

Answered by somi173
30

Answer:

The required answer is  p = -12/13

Step-by-step explanation:

Given vectors are

u = 4i + (2p/3) j + pk

v = i + 2j + 3k

Given that the vectors are Parallel.

We know that if two vectors are parallel then Their dot product is equal to zero.

⇒       u. v   =    0

( 4i + (2p/3) j + pk ) . ( i + 2j + 3k ) = 0

(4)(1) + (2p/3)(2) + (p)(3) = 0

4 + 4p/3 + 3p = 0

Multiplying Both sides by 3 , we get

12 + 4p + 9p = 0

13p = - 12

 The Answer is     p = -12/13

Answered by VSM0
6

Answer:

Ur required answer is 12

Step-by-step explanation:

The required answer is p = -12/13

Step-by-step explanation:

Given vectors are

u = 4i + (2p/3) j + pk

v = i + 2j + 3k

Given that the vectors are Parallel.

We know that if two vectors are parallel then Their dot product is equal to zero.

⇒ u. v = 0

( 4i + (2p/3) j + pk ) . ( i + 2j + 3k ) = 0

(4)(1) + (2p/3)(2) + (p)(3) = 0

4 + 4p/3 + 3p = 0

Multiplying Both sides by 3 , we get

12 + 4p + 9p = 0

12+p(4+9)=0

12+p(13)=0

12+p=0÷13

P=-12

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