If-4iszero of the polynomials p(x)=x2+11x+k, then find the value of k.
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Given :
P(x) = x²+11x+k
To Find:
Value of k
Solution :
Given that -4 is the zero of polynomial p(x)
Putting x = -4
p(x) = x²+11x+k
p(-4) = (-4)²+11(-4)+k
16-44+k = 0
-28+k = 0
k = 28
P(x) = x²+11x+k
To Find:
Value of k
Solution :
Given that -4 is the zero of polynomial p(x)
Putting x = -4
p(x) = x²+11x+k
p(-4) = (-4)²+11(-4)+k
16-44+k = 0
-28+k = 0
k = 28
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