Question

If x-a is the factor of 3x square - mx -na then prove that a = m+n / 3

Answer 1

If x-a is a factor, a is a root of the polynomial. [tex]3 x^{2} -mx-na=0, when x=a. So, 3a^{2}-ma-na=0. 3a^{2}=ma+na 3a^{2}=a(m+n) 3a=m+n a=(m+n)/3 [/tex]

Answer 2

Step-by-step explanatio