If 4sin(x) = 3cos(x) Find :
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4 sin(x) = 3 cos (x)
⇒sin(x)/cos(x) = 3/4
⇒tan(x) =3/4
⇒tan²x = 9/16
sec²(x) = 1+tan²x = 1+9/16 = 25/16
now putting the values
(25/16)/[4(1-9/16)]
=(25/16)/(7/4)
=25/28
⇒sin(x)/cos(x) = 3/4
⇒tan(x) =3/4
⇒tan²x = 9/16
sec²(x) = 1+tan²x = 1+9/16 = 25/16
now putting the values
(25/16)/[4(1-9/16)]
=(25/16)/(7/4)
=25/28
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Thanks, helped a lot!
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