If 4Sinx=3cosx, find the value of:
a) cosec²-cot²x+4
b) sec x
c) sin x
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Answer:
Step-by-step explanation:
Given that,
4sinx = 3cosx
⇒ sin x / cos x = 3 / 4
⇒tan x = 3 / 4 = AB/ BC
By using Pythagoras theorem,
AC² = AB² + BC²
⇒ AC² = 3² + 4²
⇒ AC² = 9 + 16
⇒AC² = 25
⇒ AC = √25
⇒ AC = 5
a) cosec² x - cot² x = (5/3)² - (4/3)² = (25/9) - (16/9) = (25 - 16 ) / 9 = 9/9 = 1.
b) sec x = 5/4
c) sin x = 3/5
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