Question

What are the zeroes of the polynomial x2 + x - 20

Answer 1

Answer:

$x = - 5 \\ \\ \\ x = 4$

Step-by-step explanation:

${x}^{2} + x - 20 \\ \\ = {x}^{2} - 4x + 5x - 20 \\ \\ = x(x - 4) \: + 5(x - 4) \\ \\ = (x + 5)(x - 4) \\ \\ \\ \\ \\ \\ \\ \\ \rm \underline \red{ZEROES \: OF \: THE \: POLYNOMIAL} \\ \\ (i) \: (x + 5) \: = 0 \\ \\ \implies \: x = - 5 \\ \\ \\ (ii) \: (x - 4) = 0 \\ \implies \: x = 4$

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Answer 2

Answer:

☞ x² + x – 20

☞ take factors of 20.

☞ substitute each factor in the place of x until you get zero.

☞ when you substitute x as 4, you will get zero therefore, you can derive that, x–4 is a zero of the polynomial.

☞ now divide the whole polynomial by x–4, you will get a quotient which is the second zero of the polynomial.

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