Question

if 4tanA=3 then the value of (8sinA-5cosA)/(6sinA-3cosA) is

(1)-2/3
(2)-4/5
(3)2/3
(4)4/5​

Answer 1

Solution:

(3) 2/3

• 4 tan A = 3

» tan A = 3/4

Now,

» (8 sin A - 5 cos A)/(6 sin A - 3 cos A)

Divide numerator and denominator by cos A

= (8 tan A - 5)/(6 tan A - 3)

= [8 (3/4) - 5] / [6 (3/4) - 3]

= (6 - 5) / (9/2 - 3)

= 1 / (3/2)

= 2/3