if 4th term of an AP is three times the first and the 7th term exceeds twice the 3rd term by 1.find the first term and the common difference.
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a+3d = 3a
a+6d = 2(a+2d)+1
d = 2a/3
a+6d = 2a + 4d +1
a+1 = 2d
d = (a+1)/2
(a+1)/2 = 2a/3
2a/3 - a/2 = 1/2
a/6 = 1/2
a = 3
d = 2
a+6d = 2(a+2d)+1
d = 2a/3
a+6d = 2a + 4d +1
a+1 = 2d
d = (a+1)/2
(a+1)/2 = 2a/3
2a/3 - a/2 = 1/2
a/6 = 1/2
a = 3
d = 2
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