Question

If 4x^2-6x-m is divisible by
(x-3), the value of m is exact​

Answer 1

Answer : 18

$\rule{100}2$

First of all, we've to find zero of the given polynomial.

x - 3 = 0

∴  x = 3

Now,

substitute the value of ' x ' in the the polynomial. It is given that x - 3 is completely divisible by 4x² - 6x - m. Hence, remainder must be zero.

$\sf 4(3)^2 - 6(3) - m = 0$

$\sf\implies 4(9) - 18 - m = 0$

$\sf\implies 36 - 18 - m = 0$

$\sf\implies 18 - m = 0$

$\sf\therefore 18 = m$

Answer : The exact value of m is 18.

$\rule{200}2$

Answer 2

Here p(3) = 0

⇒ 4(3)² – 6 × 3-m = 0

⇒ 36 – 18 – m = 0

⇒ m=18

∴ Value of m is exactly divisible by 9.

Ans - 9