Math, asked by avirathmohanty22, 2 months ago

If 4x^2+9y^2=136 and xy=10, find 2x+3y

Answers

Answered by chandanapukalyani

1

Answer:

(2x+3y)²=(2x)²+(3y)²+2.2x.3y

=4x²+9y²+12(xy)

=136+120

=256

2x+3y=-/256

= -/16² =16.

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