Math, asked by nsgregorian31, 10 months ago

if 4x^2+9y^2=69 and xy=1find 2x+3y

Answers

Answered by shauryagupta215
1

Answer:

hello

Step-by-step explanation:

idk

sacchi mai

IDK

Answered by ashok100pal
2

Answer:

9

Step-by-step explanation:

=> (2x+3y)^2 = 4x^2 + 12 xy + 9y^2. {by using identity(a+b)^2 = a^2 + 2ab + b^2}

or it can be written as by arranging

=>. (2x +3y)^2 = 4x^2 + 9y^2 + 12 xy. - eqn. 1

Since it is given that 4x^2 + 9y^2 = 69 and xy = 1,

thus putting values in eqn 1,we will get,

=> (2x + 3y)^2 = 69 + 12*1

=> (2x + 3y)^2 = 69 + 12 = 81

Now, 2x + 3y = √81

= 9

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