Math, asked by abdulgafur2596, 1 day ago

If 4x-3y-2z=0 and 2x +5y-3z=0, then:

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Answered by 27132shreyasingh

0

Answer:

Answer:Step-by-step explanation:0=04x-3y-2z = 2x+5y-3z2x-8y+z=02x+z = 8y (1)2(4x-3y-2z) -4(2x+5y-3z)=0->8x -6y -4z -8x-20y +12z=0=>8z -26y=08z

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