Question

if 4x^4*-3x^3-3x^2+x-7 is divided by 1-2x then the remainder will be ??​

Answer 1

Answer:

Remainder theorem:

$\boxed{\text{The remainer when P(x) is divided by (ax+b) is P(-b/a)}}$

Let,

$P(x)=4x^4-3x^3-3x^2+x-7$

The remainder when P(x) is divided by (-2x+1) is

$=P(\frac{1}{2})$

$=4(\frac{1}{2})^4-3(\frac{1}{2})^3-3(\frac{1}{2})^2+(\frac{1}{2})-7$

$=4(\frac{1}{16})-3(\frac{1}{8})-3(\frac{1}{4})+(\frac{1}{2})-7$

$=\frac{4}{16}-\frac{3}{8}-\frac{3}{4}+\frac{1}{2}-7$

$=\frac{4-6-12+8-56}{16}$

$=\frac{-62}{16}$

$=\frac{-31}{8}$