if 4x+5y= 14 and x-5y =16 then find the x and y??
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Explanation:
- 4x+5y=14 here a1=4, b1=5, c1 =14 then x-5y=16, here a2= 1, b2 = -5, c2=16 d=a1×b2 -a2×b1=4×(-5)-1×5=-20-5=25
- dx=c1×b2-c2×b1=14×(-4)-16×5=-70-21=91
- dy=a1×c2-a2×c1=4x 16-14×1=64-14=50
- by cramers rule x=dx÷d=91 ÷25 =3.64
- y=dy÷d =50 ÷25 =2 then,
- x=3.64
- y=2
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HEYA...
SIMPLY FIND X AND Y WITH ELIMINATION METHOD OR SUBSTITUTION METHOD ...
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