Question

if 4x=64 find [(x)^-2 divide (1/x)^-4 into x ^-6]

Answer 1

Hello Mate!

4x = 64
x = 64/4 = 16

${16}^{ - 2} \div \frac{1}{ {16}^{ - 4} } \times {16}^{ - 6} \\ {16}^{ - 2 - ( - 4) - 6} \\ {16}^{ - 2 + 4 - 6} = {16}^{ - 4} \\ \frac{1}{ {16}^{4} } = \frac{1}{65536}$

Hope it helps☺!

Answer 2

If 4x = 64
So, x = 16

x^-2 / (1/x)^-4 * x^-6
= 0.0039 / 65536 * .0000000059
= 3.51 * 10^-16