Math, asked by Anonymous, 1 year ago

If 4x=98^2-88^2 then find the value of x.

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Answers

Answered by 1234Nitish
15
4x = 98^2 -88^2
or, 4x = (98+88) (98-88)
or, 4x = (186) (10)
or, 4x = 1860
or,. x = 1860/4
or, x = 465 ans.......
I hope it will help you...

1234Nitish: welcome
Answered by ria113
15
Hey!!

Here is your answer,,

4x =  {98}^{2}  -  {88}^{2}  \\  \\ 4x = (98 - 88)(98 + 88) \\  \\ 4x = (10)(186) \\  \\ 4x = 1860 \\  \\ x =  \frac{1860}{4}  \\  \\ x = 465 \\  \\  \\
Hope it helps you...

Thanks ^-^

Anonymous: Thanks rise sis.
Anonymous: ria*
ria113: welcm ^-^
ria113: nd thanx for brainliest
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