if 4x-y=4;x-4y=16 then find x-y=?
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4x + y = 34 .....(I)
x + 4y = 16 .......(II)
Adding (I) and (II) we get
5x + 5y = 50
⇒ x + y = 10 ......(III)
Subtracting (II) from (I) we get
3x - 3y = 18
⇒ x - y = 6 ......(IV)
(III) + (IV)
2x = 16
⇒ x = 8
Putting the value of x in (I) we get
4 (8) + y = 34
⇒ y = 34 - 32 = 2
⇒ y = 2
Thus, x = 8 , y =
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