Question

if 4x²+25y²=41 and xy=2 find the value of 2x–5y

Answer 1

check this pic........

Answer 2

Hey !!!! Your answer =>

$4 {x}^{2} + 25 {y}^{2} = 41 \\ xy = 2 \\ \\ ( {2x)}^{2} + ( {5y)}^{2} = 41 \\ \\ (2x - 5y) + 2 \times 2x \times 5y = 41 \\ \\ ( 2x - 5y) + 20 \times xy = 41 \\ \\ ( 2x - 5y) + 40 = 41 \\ \\ 2x - 5y = 41 - 40 \\ \\ 2x - 5y = 1$

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