Question

if 4x⁴-(a-1)x³+ax²-6x+1 is divided by 2x-1 then' a 'is equal to​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

After dividing the given equation by 2x - 1, the value of ‘a’ we get is 13.

Step-by-step explanation:

Let us call and represent the given equation to us as P(x) ,

Therefore, $P(x) = 4x^4-(a-1)x^3+ax^2-6x+1 = 0$

So if we divide P(x) by 2x-1

Lets first find the value of x in this above equation :

2x-1 = 0

2x = 1

Therefore x= 1/2

Now by substituting the value of x that we calculated in P(x) we will get -

$P(1/2) = 4 (1/2)^4 - (a-1) (1/2)^3 + a(1/2)^2 -6(1/2) + 1 =0$

$4 [(1)^4/(2)^4] -(a-1)[(1)^3/(2)^3] +a[(1)^2/(2)^2] - (3) +1 =0$

$= (1/4) -[(a-1)/8]+(a/4) -2 = 0$

$[ (2) -(a-1) + 2a- 16 ]/8 = 0$

Taking denominator to the right hand side we get :

$2+1-16-a+2a = 0$

$3-16+a=0$

$-13+a=0$

Taking -13 to the right hand side we get :

$a =13$

Therefore according to our above calculation, we get the value of ‘a’ as 13.

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