Question

if(5,-2) is a solution of the equation kx-3y+4=0 then the value of k is​

Answer 1

kx - 3y + 4 = 0

( 5 ,-2 )

x = 5 y = -2

kx - 3y + 4 = 0

k(5) - 3(-2) + 4 = 0

5k + 6 + 4 = 0

5k = -10

k = -10/5

k = -2

i think this is the answer...........I hope this helps u

Answer 2

Answer:

k=-2

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