Math, asked by jas22663, 6 months ago

If 5, 2k-3, 9 are in A.P. then the value of ‘k’ is:​

Answers

Answered by SohamAgarwal
1

Answer:

Value of k is 5

Step-by-step explanation:

First, we need to find the common difference.

9 = a + 2d

9 = 5 + 2d

d = 2

Now, as 2k - 3 is the second term of this AP,

2k - 3 = a + d = 5 + 2 = 7

2k = 10

k = 5

Answered by fenisebastian
0

ANSWER

A

1

=2K

A

2

=3K−1

A

3

=8

D=D

A

2

−A

1

=A

3

−A

2

3K−1−2K=8−(3K−1)

K−1=8−3K+1

K+3K=8+1+1

4K=10

K=

4

10

K=2.5

we get, K=2.5

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