Question

if 5 cot theta = 4, evaluate 2 sin square theta + 3 cos square theta / 7 sin theta cos theta
​

Answer 1

Answer:

Given

5cot theta=4

cot theta=4/5

therefore, we get AB=4,BC=5

therefore, by Pythagoras theorem

AC^2=AB^2+BC^2

AC^2=4^2+5^2

AC^2=16+25

AC=√41

therefore , sin theta=5/√41

cos theta=4/√41

therefore 2sin^2 theta+3cos^2 theta/7 sin theta cos theta

2×(5/√41)^2+3×(4/√41)^2/7×5/√41×4/√41

(50/41+48/41)/140/41

98/140

7/10

please mark it as brainliest if it helps you

Answer 2

2sin²theta+3 cos²theta /7 sin theta cos theta =0.7