If - 5 is a root of the quadratic equation 2x^2 +px - 15 = 0 and the quadratic equation p( x^2 + x ) + k = 0 has equal roots, find the value of k.
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Here is your answer dear:-
In equation (2) I have added K by giving apostrophe.
I hope it will help you.
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In equation (2) I have added K by giving apostrophe.
I hope it will help you.
✌✌✌✌✌
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NainaMehra:
it's wrong
Answered by
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Given Quadratic equation is 2x^2 + px - 15 = 0.
(i)
Given that -5 is a root of quadratic equation.
Substitute x = -5, we get
⇒ 2(-5)^2 + p(-5) - 15 = 0
⇒ 50 - 5p - 15 = 0
⇒ 35 - 5p = 0
⇒ p = 7.
(ii)
Given that p(x^2 + x) + k = 0 has equal roots.
Substitute p = 7, then the equation becomes:
⇒ 7(x^2 + x) + k = 0
⇒ 7x^2 + 7x + k = 0
Here, a = 7, b = 7, c = k.
∴ D = 0
⇒ b^2 - 4ac = 0
⇒ (7)^2 - 4(7)(k) = 0
⇒ 49 - 28k = 0
⇒ 49 = 28k
⇒ k = (7/4).
Therefore, the value of k = 7/4.
Hope this helps!
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