Question

If -5 is a root of the quadratic equation 2x^2+px-15=0 and the quadratic equation

Answer 1

$2 {x}^{2} + px - 15 = 0 \\ 2(- 5)^{2} + p( - 5) - 15 = 0 \\ 2(25) - 5p - 15 = 0 \\ 50 - 5p - 15 = 0 \\ 35 - 5p = 0 \\ 35 = 5p \\ 35 \div 5 = p \\ 7 = p$

This will help you very much

Answer 2

Find factor:

Step-by-step explanation:

$\ Given \ value:\\\\\ root:\\\\x = -5\\\\\ quadratic \ equation:\\\\2x^2+px-15=0 \\\\\ Find: \\\\\ \ value\ of \ p = ?\\\\\ Solution:\\\\\ put \ the \ value \ of \ x \ in \ given \ equation:\\\\2x^2+px-15=0 \\\\ \rightarrow 2(-5)^2+p(-5)-15=0 \\\\ \rightarrow 2(25)-5p-15=0 \\\\\rightarrow 50-5p-15=0 \\\\\rightarrow 35-5p=0 \\\\\rightarrow 35=5p \\\\\rightarrow 5p=35 \\\\\rightarrow p= \frac{35}{5} \\\\\rightarrow p=7$

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