If (-5) is remainder when 2x ^3-mx^2+9 is divided by 2x+1, find the value of m.
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Answers
Answered by
5
2x+1=0
x=-1/2
put x=-1/2 in dividend
2 (-1/2)^3-m (-1/2)^2+9=-5
2 (-1/8)-m/4+9=-5
-1/4-m/4=-14
-1/4 (1-m)=-14
(1-m)=-14×-4
1-m=56
m=-55
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Answered by
3
Hey mate ,
Here is your answer ,
2x+1=0
x=-1/2
put x=-1/2 in dividend
2 (-1/2)^3-m (-1/2)^2+9=-5
2 (-1/8)-m/4+9=-5
-1/4-m/4=-14
-1/4 (1-m)=-14
(1-m)=-14×-4
1-m=56
m=-55
Hope it will help you !!!
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