if 5 is the one of the roots of 2x²+kx-75=0 the k=
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Answered by
6
x = 5 if 5 is one of roots.
2(5²)+k(5)-75 = 0
2(25) + 5k - 75 = 0
50 - 75 + 5k = 0
5k = 25
k = 5 .
Hope helped !
2(5²)+k(5)-75 = 0
2(25) + 5k - 75 = 0
50 - 75 + 5k = 0
5k = 25
k = 5 .
Hope helped !
nidhinikki:
Tq so much
Answered by
3
2x^2+kx-75=0
if x=5,
2(5)^2 + k(5) - 75 = 0
2(25) + 5k - 75 = 0
50 + 5k - 75 = 0
-25 = -5k
k = -25/-5 = 5
if x=5,
2(5)^2 + k(5) - 75 = 0
2(25) + 5k - 75 = 0
50 + 5k - 75 = 0
-25 = -5k
k = -25/-5 = 5
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