If 5 is the zero of the polynomial x2+3x+ t find t
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0
Your answer is ----
Let, f(x) = x2+3x+ t
Since , 5 is the zero of the given polynomila
therefore ,
f(5) = 0
=> 5^2 + 3×5 + t = 0
=> 25 + 15 + t = 0
=> t = -40
Let, f(x) = x2+3x+ t
Since , 5 is the zero of the given polynomila
therefore ,
f(5) = 0
=> 5^2 + 3×5 + t = 0
=> 25 + 15 + t = 0
=> t = -40
Answered by
7
Given , a quadratic polynomial having 'x ' as its variable .
p( x ) = x^2 + 3 x + t
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since , 5 is the zero of the polynomial
p ( x ) then p ( x ) should be equal to zero.
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let us solve it for p ( 5 )
p ( 5 ) = (5 )^2 + 3 (5 )+ t
p ( 5 ) = 25 + 15 + t
p( 5 ) = 40 + t
since , p( 5) should be equal to zero ,
therefore , p ( 5 ) = 0
= > 40 + t = 0
=> t = - 40
_______________________________
Your Answer : t = - 40
_______________________________
p( x ) = x^2 + 3 x + t
_______________________________
since , 5 is the zero of the polynomial
p ( x ) then p ( x ) should be equal to zero.
_______________________________
let us solve it for p ( 5 )
p ( 5 ) = (5 )^2 + 3 (5 )+ t
p ( 5 ) = 25 + 15 + t
p( 5 ) = 40 + t
since , p( 5) should be equal to zero ,
therefore , p ( 5 ) = 0
= > 40 + t = 0
=> t = - 40
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Your Answer : t = - 40
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