if (5,k) is a solution of a linear equation 2x + y - 6 =0 then find the value of k
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Answered by
54
hi man here is your answer
2 x + y -6 =0
( 5 , k)
x= 5 , y=k
2(5) + k -6 = 0
10 + k - 6 =0
4 + k = 0
k = -4
Answered by
4
Given,
- (5,k) is the solution of the linear equation 2x + y - 6 =0.
To find,
- We have to find the value of k.
Solution,
We can simply find the value of k by substituting the point (5,k) in the linear equation 2x + y - 6 =0.
2x + y - 6 =0
Since (5,k) is the solution of the linear equation 2x + y - 6 =0, then (5,k) must satisfy the given linear equation.
Now, substituting (5,k) in the above equation, we get
2(5) + k -6 = 0
10 + k -6 = 0
k +4 = 0
Shifting +4 from LHS to RHS, we get
k = -4
Hence, if (5,k) is a solution of a linear equation 2x + y - 6 =0 then the value of k is -4.
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