Question

if 5 ke power 2x+1÷25=125.find the value of x. give my answer fast plz.....

Answer 1

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$5 {}^{2x} \times 5 \div 5 {}^{2} = 5 {}^{3}$


$5 {}^{2x + 1} = 5 {}^{5}$


cancelling the bases. . ......


$2x + 1 = 5 \\ \\ 2x = 4$


$x = \frac{4}{2} = 2$


x=2


Hope it helps you


@ Prabhudutt

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!!}}}$

$<b>$
$5 {}^{2x + 1} \div 25 = 125 \\ \frac{5 {}^{2x + 1} }{5 {}^{2} } = 5 {}^{3} \\ 5 {}^{2x + 1 - 2} = 5 {}^{3} \\ 5 {}^{2x - 1} = 5 {}^{3} \\ on \: the \: same \: base \: hence \\ 2x - 1 = 3 \\ 2x = 3 + 1 \\ 2x = 4 \\ x = \frac{4}{2} \\ x = 2$
$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\:helps\: you}}}}}}}}}}}}}}}$