If 5 men take time do a work is 5 day
the 10 men done same work in how many days?
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Answer:
the 10 men can do same work in 2.5 days
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If A and B can together finish it in t days with A and B finishing the work in a and b days respectively,
1/a + 1/b = 1/t
Calculation:
Time taken by 5 men = 10 days
⇒ 1 man = 50 days
⇒ 1 man per day work = 1/50
Now,
Time taken by 10 boys = 5 days
⇒ 1 boy = 50 days
⇒ 1 boy per day work = 1/50
ATQ,
10m + 2b = 10 × 1/50 + 2 × 1/50 = 6/25 = 25/6 days
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