Question

If 5 sin 4 0    , find: [3]

(i) sec 

(ii) tan cot   ​

Answer 1

Answer:

ANSWER

Divide the numerator and denomenator by cosθ

cosθ

5sinθ+2cosθ

cosθ

5sinθ−3cosθ

⇒

cosθ

5sinθ

+

cosθ

2cosθ

3cosθ

5sinθ

−

cosθ

3cosθ

⇒

5tanθ+2

5tanθ−3

Substituting the value of 5tanθ, we get

⇒

4+2

4−3

=

6

1