In the figure angle AOC=55° then angleACB= a)55°,b)90° ,C)110° and d)70°
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∠ADC=
2
1
∠AOC
(Angle subtended by a chord on mayor area is half of that subtended on center)
∴∠ADC=
2
1
×130=65
∘
Now, ADCB is cyclic quadrilateral ⇒
Sum of opposite Angles is 180
∘
∴∠ABC+∠ADC=180
∘
∠ABC+65=180
∘
∠ABC=115
∘
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70 is your correct answer
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