Question

If 5 sin teta=3,then tan teta=___ pls help me

Answer 1

Answer:

Answer

sin θ=

5

3

secθ−tanθ

secθ+tanθ

Multiplying numerator and denominator by cos θ

secθ−tanθ

secθ+tanθ

=

1−sinθ

1+ssin

=

1−

5

3

1+

5

3

Multiplying numerator and denominator by 5,

=

5−3

5+3

=4

Step-by-step explanation:

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Answer 2

Answer:

$\huge{\fbox{\fbox{\fbox{\color{magenta}{A}{\color{red}{N}{\color{aqua}{S}{\color{orange}{W}{\color{blue}{E}{\color{pink}{R}}}}}}}}}}$

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Given:-

$\sf{5 \sin(θ) = 3}$

$\large\sf{\color{navy}\boxed{\color{red}{\sin(θ) = \frac{3}{5} }}}$

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Proof:-

We know that,

$\sf {⇒{ \cos}^{2} θ = 1 - { \sin }^{2} θ}$

$\sf{⇒{ \cos }^{2} θ = 1 - ( \frac{ {3}}{5} ) ^{2}}$

$\sf{⇒{ \cos }^{2} θ = 1 - \frac{9}{25}}$

$\sf {⇒{ \cos}^{2} θ = \frac{25 - 9}{25}}$

$\sf{ ⇒{ \cos}^{2} θ = \frac{16}{25} }$

$\sf{⇒{\cos θ = \sqrt \frac{16}{25 }} }$

$\sf{ ⇒\cosθ = \frac{4}{5} }$

$\large\sf{\color{navy}\boxed{\color{red}{⇒ \cosθ = \frac{4}{5}}} }$

$\sf {⇒\tan \: θ = \frac{ \sinθ }{ \cosθ} }$

Substitute the values of sin θ and cos θ.

$\sf{ ⇒\tan \: θ = \frac{ \frac{3}{5} }{\frac{4} {5}}}$

$\large\sf{\color{blue}\boxed{\color{pink}{ ⇒\tanθ = \frac{3}{4}}}}$

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$\huge{\underline{\underline{\color{aqua}{Be\: brainly}}}}$