Question

if 5 sin teta -7 cos teta =0then find the value of sec teta

Answer 1

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Answer 2

Answer:

$5\:sin\theta \:-7cos\theta =0\:;\:5sin\theta =7cos\theta \:;\:\frac{sin\theta }{cos\theta }=\frac{7}{5}=tan\theta \:;\:tan^2\theta =\left(\frac{7}{5}\right)^2;\:tan^2\theta +1=\frac{49}{25}+1;\:sec^2\theta =\frac{74}{25};\:sec\theta =\pm \frac{\sqrt{74}}{5}$

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