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If 5 sine - 12 cos 0 = 0 then find the value of sec 0
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Ans--> Secθ = 13 / 5
I think question is like this
If 5Sinθ - 12 Cosθ = 0 then find the value of Secθ.
Solution---> ATQ,
5Sinθ - 12 Cosθ = 0
=> 5 Sinθ = 12 Cosθ
=> Sinθ / Cosθ = 12 / 5
=> tanθ = 12 / 5
We have an identity ,
1 + tan²θ = Sec²θ
=> Sec²θ = 1 + tan²θ
Putting tanθ = 12 / 5 , we get
= 1 + ( 12 / 5 )²
= 1 + (144 / 25)
= ( 25 + 144 ) / 25
=> Sec²θ = 169 / 25
=> Secθ = √(169/25)
=> Secθ = 13 / 5
Additional information --->
(1) Sin²θ + Cos²θ = 1
(2) 1 + Cot²θ = Cosec²θ
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