Math, asked by Iihgfgbbhu9899, 1 year ago

If 5 tan theta -4 =0 find the value of 5 sin theta - 4 cos theta/5 sin theta + 4 cos theta

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Answered by Anonymous
85
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Answered by arun9399
44

5 \tan \alpha  - 4 = 0 \\ so \:  \tan \alpha  = 4 \div 5 \\ find \: value \: of \:( 5 \sin \alpha  - 4 \cos \alpha ) \div (5 \sin \alpha  + 4 \cos \alpha ) \\ take \:  \cos \alpha  \:  \: common \:  \\  \cos \alpha (5 \tan \alpha  - 4) \div  \cos \alpha (5 \tan   + 4 )  \\ we \: have \: now \:  \\ (5 \tan \alpha - 4) \div (5 \tan \alpha  + 4) \\ now \: put \: the \: value \: of \:  \tan \alpha  = 4 \div 5 \\  \: we \: get \: answer \: 0
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